   Chapter 31, Problem 46PE

Chapter
Section
Textbook Problem

Data from the appendices and the periodic table may be needed for these problems.(a) Calculate the activity R in curies at 1.00 g of 226Ra. (b) Discuss why your answer is not exactly 1.00 Ci, given that the curie was originally supposed to be exactly the activity of a gram of radium.

To determine

(a)

The activity R in curies of 1.00 g of R226a ?

Explanation

Given info:

m=1g

Formula used:

Activity,

R=0.693Nt1/2

Calculation:

Number of atoms in 1 g of Radium,

N=1226×6.02×1023=2.6646×1021atoms

Half-life of R226a=1.6×103y

Substituting,

R=0

To determine

(b)

Why your answer is not exactly 1.00 Ci, given that the curie was originally supposed to be exactly the activity of a gram of radium?

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