= 105° = 75° = 135° = 45° v2 KAN 32 64 v2 NR 64R 32 Water sprinkler: 45° 135°

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter12: Angle Relationships And Transformations
Section: Chapter Questions
Problem 4MCQ
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A lawn sprinkler is constructed in such a way that d /dt is constant, where ranges between 45° and 135°. The distance the water travels horizontally is      x = v2sin2/32 , 45° ≤ ≤ 135° where v is the speed of the water. Find dx/dt and explain why this lawn sprinkler does not water evenly. What part of the lawn receives the most water?

= 105°
= 75°
= 135°
= 45°
v2
KAN 32 64
v2
NR 64R 32
Water sprinkler: 45°
135°
Transcribed Image Text:= 105° = 75° = 135° = 45° v2 KAN 32 64 v2 NR 64R 32 Water sprinkler: 45° 135°
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