   Chapter 31, Problem 74PE

Chapter
Section
Textbook Problem

The fact that BE/A is greatest for A near 60 implies that the range at the nuclear force is about the diameter of such nuclides. (a) Calculate the diameter at an A = 60 nucleus. (b) Compare BE/A for 58Ni and 90Sr. The first is one of the most tightly bound nuclides, while the second is larger and less tightly bound.

To determine

(a)

The diameter of a nucleus of atomic mass number 60.

Explanation

Given info:

The atomic mass number of nucleus is 60 .

The value of empirical constant r0 is 1.2fm .

Formula used:

To find the radius of nucleus is,

r=r0A13

Equation-2

Here, r0 is the empirical constant and A is the atomic mass number.

Calculation:

To find the radius of nucleus,

r=1

To determine

(b)

To compare the difference in binding energy per nucleon of N58i and S90r .

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