   Chapter 31, Problem 78PE

Chapter
Section
Textbook Problem

Integrated ConceptsA 2.00−T magnetic ?eld is applied perpendicular to the path of charged particles in a bubble chamber. What is the radius of curvature of the pain of a 10 MeV proton in this field? Neglect any slowing along its pam.

To determine

The radius of curvature of the path of a10 MeVproton in this field, a2.00 Tmagnetic field is applied perpendicular to the path of charged particles in a bubble chamber.

Explanation

Given info:

E=10 MeV

B=2 T

Formula used:

For energy in magnetic field, the relation between energy and velocity is

E12mv2

Radius of curvature of the path of proton in magnetic field is

rmvqB

Calculation:

Substituting the given values of energy in relation with velocity, we get

Emc2

Energy-Mass relation of proton is 938 MeV

m938c2m938(3×108)2m1

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