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Physics for Scientists and Enginee...

10th Edition
Raymond A. Serway + 1 other
ISBN: 9781337553278

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Chapter
Section
BuyFindarrow_forward

Physics for Scientists and Enginee...

10th Edition
Raymond A. Serway + 1 other
ISBN: 9781337553278
Textbook Problem

The current in a 4.00 mH-inductor varies in time as shown in Figure P31.8. Construct a graph of the self-induced emf across the inductor over the time interval t = 0 to t = 12.0 ms.

images

To determine

To draw: The graph of the self induced emf across the conductor for the given time interval.

Explanation

Explanation

Given Info: The inductance of the material is 4.00mH the time interval is from t=0s to t=40s .

The formula to calculate induced emf is,

ε=Ldidt

Here,

ε is the induced emf.

L is the inductance.

didt is the rate of change of current.

Tabulate the variation of current with respect to time according to given graph.

t dtms di(i2i1) mA L mH ε=Ldidt mV
0 to 2 ms 2 ms 10=1 4 2
2 to 4 ms 2

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