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College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

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BuyFindarrow_forward

College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

Show that the total energy released in the proton—proton cycle is 26.7 MeV, considering the overall effect in 1 H+ 1 H 2 H+ e + + v e , 1 H+ 2 H 3 H e + γ , and 3 H+ 3 He 4 H e + 1 H+ 1 H and being certain to include the annihilation energy.

To determine

To verify:

That the total energy released in the proton-proton cycle is 26.7 MeV, considering the overall effect in H1+H1H2+e++υe,H1+H2H3e+γ and H3e+H3eH4e+H1+H1 and being certain to include the annihilation energy?

Explanation

Given info:

  m(H1)=1.007825032um(H4e)=4.002602uEnergy of 1 u = 931.5MeV

Formula used:

Energy,

  E=Δmc2

Calculation:

Overall effect equation,

  2e<

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