The determination of chloride in isotope dilution experiment is done by the mixing of 5.0 mg of sodium chloride with specific activity of 3.6 × 10 4 c p s / m g which contains 38 C l . The half time of 38 C l is 37.3 min. The total amount of chloride present in original sample is to be determined when isolation of pure AgCl of amount 400mg was happened and the counting rate of material is 38cps above the background of 150min. Concept introduction: The decay constant is determined by using the formula of half time which is given as- t 1 / 2 = 0.693 λ Also, the mass of chloride ion in sample is calculated by following formula- m x = R t R m × m m − m t ……………… (1) Where, m x = mass of inactive sample R t = counting rate R m = counting rate of inactive analyte m m = isolated mass m t = mass of radioactive tracer

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Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213
BuyFind

Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

Solutions

Chapter 32, Problem 32.16QAP
Interpretation Introduction

Interpretation:

The determination of chloride in isotope dilution experiment is done by the mixing of 5.0 mg of sodium chloride with specific activity of 3.6×104cps/mg which contains 38Cl. The half time of 38Cl is 37.3 min. The total amount of chloride present in original sample is to be determined when isolation of pure AgCl of amount 400mg was happened and the counting rate of material is 38cps above the background of 150min.

Concept introduction:

The decay constant is determined by using the formula of half time which is given as-

t1/2=0.693λ

Also, the mass of chloride ion in sample is calculated by following formula-

mx=RtRm×mmmt ……………… (1)

Where,

mx = mass of inactive sample

Rt = counting rate

Rm = counting rate of inactive analyte

mm = isolated mass

mt = mass of radioactive tracer

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