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ChemistryPrinciples of Instrumental AnalysisThe half-life of ß emitter that is potassium -42 is 12.36h. The fraction of radionuclide is to be determined from the sample of 1,10,20,30,40,50,60,70,80,90 and 100h.The graph is to be plotted between the fraction remaining and the time which is required for the fraction to fall 1% is to be determined. Concept introduction: According to first order of kinetics: ln ( N N 0 ) = − λ t Here, N and N o are final and initial concentrations, λ is decay constant and t is time. t 1 / 2 ( h a l f − t i m e ) = ln 2 λ Here, t 1 / 2 is half-life time.Start your trial now! First week only $4.99!*arrow_forward*

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7th Edition

Douglas A. Skoog + 2 others

Publisher: Cengage Learning

ISBN: 9781305577213

Chapter 32, Problem 32.2QAP

Interpretation Introduction

**Interpretation:**

The half-life of ß emitter that is potassium -42 is 12.36h. The fraction of radionuclide is to be determined from the sample of 1,10,20,30,40,50,60,70,80,90 and 100h.The graph is to be plotted between the fraction remaining and the time which is required for the fraction to fall 1% is to be determined.

**Concept introduction:**

According to first order of kinetics:

Here, N and N_{o} are final and initial concentrations,

Here,