The counting rate of sample 64 C u is 4225cpm. The counting rate of sample after 10.00hr is 2898cpm. The half time of the sample 64 C u is to be determined. Concept introduction: According to first order of kinetics: ln ( N N 0 ) = − λ t Here, N and N o are final and initial concentrations, λ is decay constant and t is time. t 1 / 2 ( h a l f − t i m e ) = ln 2 λ Or, t 1 / 2 = 0.693 λ Here, t 1 / 2 is half-life time.

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Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213
BuyFind

Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

Solutions

Chapter 32, Problem 32.9QAP
Interpretation Introduction

Interpretation:

The counting rate of sample 64Cu is 4225cpm. The counting rate of sample after 10.00hr is 2898cpm. The half time of the sample 64Cu is to be determined.

Concept introduction:

According to first order of kinetics:

ln(NN0)=λt

Here, N and No are final and initial concentrations, λ is decay constant and t is time.

t1/2(halftime)=ln2λ

Or,

t1/2=0.693λ

Here, t1/2 is half-life time.

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