To find:
The equation of the tangent and parallel to the line
Answer to Problem 53E
The equation of the line is
Explanation of Solution
Given:
The tangent to the curve
Concept used:
The equation is in slope −intercept form,
An equation for the line through the point
Calculation:
The function
The derivative of a function
Differentiating the equation (1) with respect to
The derivative is slope of the tangent line so in order to the slope of the tangent line
The derivative of constant is zero
An equation for the line through the point
Chapter 3 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning