   Chapter 32, Problem 60PE

Chapter
Section
Textbook Problem

A 1.00−MT bomb exploded a few kilometers above the ground deposits 25.0% of its energy into radiant heat.(a) Find the calories per cm2 at a distance of 10.0 km by assuming a uniform distribution over a spherical surface at that radius.(b) If this heat falls on a person’s body, what temperature increase does it cause in the affected tissue, assuming it is absorbed in a layer 1.00−cm deep?

To determine

(a)

The radiant heat at a distance of 10.0 km in cal per cm2 due an explosion of a 1.00 MT bomb.

Explanation

Given:

Energy of the bomb

E=1MT

Percentage of energy converted into radiant heat

E0=25% of E

Distance at which the radiant energy is measured.

r=10.0 km

Calculation:

Express the energy of the bomb in cal.

E=1 MT×9.993× 10 14cal1 MT=9.993×1014cal

Calculate the energy converted into radiant heat.

E0=25% of E=25100×9.993×1014cal=2

To determine

(b)

The change in the temperature of the human body if this radiation is absorbed by 1 cm thick tissue.

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