   Chapter 33, Problem 47PE

Chapter
Section
Textbook Problem

Integrated ConceptsThe primary decay mode for the negative pion is (a) What is the energy release in MeV in this decay? (b) Using conservation of momentum, how much energy does each of the decay products receive, given the is at rest when it decays? You may assume the muon antineutrino is massless and has momentum just like a photon.

To determine

(a)

Amount of energy released in the decay of negative pion given by, πμ+ν¯μ

Explanation

Given:

Given reaction is πμ+ν¯μ

Formula used:

Energy released in a decay process

= Rest energy of initial particle − sum of energies of decay products

Calculation:

In this problem the negative pion decays by πμ+ν¯μ

Rest energy of π particle =139

To determine

(b)

The amount of energy received by decay products.

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