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Calculus: Early Transcendentals

8th Edition
James Stewart
ISBN: 9781285741550

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Calculus: Early Transcendentals

8th Edition
James Stewart
ISBN: 9781285741550
Textbook Problem

Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy.

24. y sec x = x tan y

To determine

To find: The derivative dxdy by the use of implicit differentiation.

Explanation

Given:

The equation is ysecx=xtany.

Derivative rules:

(1) Chain rule: If y=f(u) and u=g(x) are both differentiable function, then

dydx=dydududx.

(2) Product Rule: If f1(x) and f2(x) are both differentiable, then

ddx(f(x)g(x))=f(x)ddx(g(x))+g(x)ddx(f(x)).

Calculation:

Let y be an independent variable and x be a dependent variable.

The given equation is,

ysecx=xtany

Differentiate implicitly with respect to y on both sides of the above equation,

ddy(ysecx)=ddy(xtany)

Apply the product rule (2) and simplify the terms,

yddy(secx)+secxddy(y)=xddy(tany)+tanyddy(x)yddy(secx)+secx(1)=x(sec2

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