Concept explainers
(a) The volume of a growing spherical cell is
(i) 5 to 8μm
(ii) 5 to 6μm
(iii) 5 to 5.1μm
(b) Find the instantaneous rate of change of V with respect to r when r = 5μm.
(c) Show that the rate of change of the volume of a sphere with respect to its radius is equal to its surface area. Explain geometrically why this result is true. Argue by analogy with Exercise 13(c).
Trending nowThis is a popular solution!
Chapter 3 Solutions
Single Variable Calculus: Early Transcendentals
Additional Math Textbook Solutions
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
Precalculus: Mathematics for Calculus (Standalone Book)
University Calculus: Early Transcendentals (4th Edition)
Calculus: Early Transcendentals (3rd Edition)
Precalculus: A Unit Circle Approach (3rd Edition)