Figure P24.24

Q: Radio waves from a star, of wavelength 2.50 3 102 m, reach a radio telescope by two separate paths,…

A: The path of the radio waves is,

Q: What is the separation between two slits for which 530-nm green light has its first maximum at an…

A:

Q: A sodium light, having wavelength 632.8 nm, is used to view a soap film to make it look black when…

A: For destructive interference  2nt=mλ t= λ2n

Q: A riverside warehouse has two open doors, as in Figure P24.11. Its interior is lined with a…

A: Write the expression for angle from the original beam

Q: Consider the surface of a soap bubble as a flat thin film with refractive index n=1.28 surrounded by…

A:

Q: n = 1.45

A: Refer attachment

Q: Jimin applies a coating on a piece of glass to reduce its reflectivity when light with a frequency…

A: Determine the wavelength of the light.

Q: A single slit of width 3.0 μm is illuminated by a light of wavelength 680 nm. What is the intensity…

A:

Q: Light is incident from air (n= 1.00) on a thin film of water (n= 1.33) that is on a car's windshield…

A: Given:refractive index(RI) of air, na = 1.00think film is of water, with RI, nw = 1.33glass RI, ng =…

Q: Show work

A: The equation for the transmitted intensity is

Q: The wavelength of red helium-neon laser light in air is 632.8 nm. (a) What is its frequency? Hz (b)…

A: (a) The frequency of light is given by, f=c/λ where c=3.00×108 m/s, the speed of light in a vacuum…

Q: The wavelength of red helium-neon laser light in air is 632.8 nm. (a) What is its frequency? Hz (b)…

A: The wavelength of red helium-neon laser light in air is 632.8 nm. (a) What is its frequency? (b)…

Q: Polarizers can be made based on the principle of Brewster angle. In Fig. 2, a light ray (with 50%…

A: Answer:-  Given  Refractive index (n1) = 1.33  Refractive index (n2) = 1.5  Refractive index (n3) =…

Q: A thin uniform film of refractive index 1.750 is placed on a sheet of glass with refractive index…

A: Given: The refractive index of the thin film is = 1.750 The refractive index of sheet of glass is =…

Q: A company trains a fleet of drones to seek out exposed empty plastic water bottles in a landfill.…

A: Given that:nplastic=1.575 t=625 μm=625×10-6 mnwater=1.33nair=1

Q: Interference effects are produced at point P on a screen as a result of direct rays from a 5.00 x…

A: Consider a simplified diagram for the above problem.

Q: A thin layer of oil (n = 1.25) is floating on water (n = 1.33). What is the minimum nonzero…

A: λ = 530 nm n of oil = 1.25 n of water = 1.33

Q: A surface of glass with refraction index of 1.83 is covered with a thin film with refraction index…

A: (a)   The smallest thickness of the film when the light of the wavelength 412 nm is most strongly…

Q: Problem 16: Consider a 570 nm light falling on a single slit of width 1.5 μm. Randomized…

A: The relation to obtain mth order destructive interference or mimima for a single slit of width w is…

Q: A thin film of oil (n = 1.44) of thickness 436 nm with air on both sides is illuminated with white…

A: Given data The refractive index of oil is given as n = 1.44, The thickness of the film is given as…

Q: A monochromatic light of wavelength 316 nm in air is passing through a piece of glass of index of…

A:

Q: An oil film (n = 1.48) of thickness 83.3 nm floating on water (n=1.33) is illuminated with white…

A: The reflected light from the top of the oil film undergoes phase reversal.   1.48>1.33 , the…

Q: A thin film of glycerin (n = 1.473) of thickness 525 nm with air on both sides is illuminated with…

A: Given data: n = 1.473 Thickness (t) = 525 nm Need to determine the wavelength is illuminated near to…

Q: Figure CQ24.7 shows rays with wavelength l incident from above onto thin films surrounded by air.…

A: Given:Wavelength of light = λIncident on a medium having refractive index = 1.5

Q: A certain kind of glass has an index of refrac- tion of 1.646 for blue light of wavelength 430 nm…

A:

Q: A 500-nm-wavelength beam of light illuminates a soap film with air on both sides and an index of…

A: In this question, the wavelength of light and refractive index of film is given. To calculate…

Q: A soap film, 4.5 x 10-7 m thick, is illuminated by white light normal to its surface. The index of…

A:

Q: A thin film with an index of refraction of 1.35 is applied to an automobile windshield (with air…

A:

Q: Figure P24.69 shows d- radio-wave transmitter and a receiver, both h = 50.0 m above the ground and d…

A: (a) The longest wavelength that interfere constructively is

Q: White light is incident at near normal on a thin film of thickness 542 nm and index of refraction n…

A:

Q: A light is incident normally on a thin (n = 1.33) suspended in the air. What is the second minimum…

A: The combined effect of two or more waves intersecting at a point, is know as interference. It can…

Q: Given solution A&B A) What is the longest wavelength of light that will experience constructive…

A:

Q: Light of wavelength A = 629 nm is incident %3D from vacuum onto glass of index of refraction n =…

A:

Q: An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on…

A:

Q: You are standing in air and are looking at a flat piece of glass (n = 1.52) on which there is a…

A: Data Given , nglass = 1.52 nplastic = 1.61 Wavelength in vaccum ( λvaccum) = 562 nm The condition…

Q: thin soap film (mu=1.33) is illuminated by white light at angle of incidence I = sin^-1(4/5) . In…

A:

Q: What is the highest order bright fringe that will be observed when green light of wavelength 550 nm…

A: Answer Given  data wavelength(λ )= 550 nm  Slit spacing (d)  = 11 µm    The condition for nth order…

Q: A thin film of polystyrene n=1.49 coats a piece of glass n=1.55. When illuminated from above, the…

A:

Q: Jimin applies a coating on a piece of glass to reduce its reflectivity when light with a frequency…

A:

Interference of Light

The word "constructive" signifies addition in interference. Constructive interference occurs when the path of the waves that start from the slit differs by 1 entire wavelength or in the intervals of the same. Hence, the waves that are presented on the screen are in phase (crest to crest/trough to trough). The waves interfering constructively forms bright fringes on the screen.