Let v 1 be the velocity of light in air and v 2 the velocity of fight in water. According to Fermat’s Principle, a ray of fight will travel from a point A in the air to a point B in the water by a path ACB that minimizes the time taken. Show that sin θ 1 sin θ 2 = v 1 v 2 where θ 1 (the angle of incidence) and θ 2 (the angle of refraction) are as shown. This equation is known as Snell’s Law.
Solution Summary: The author explains how a ray of light travels from point A to C in air and point C to B in water.
Let
v
1
be the velocity of light in air and
v
2
the velocity of fight in water. According to Fermat’s Principle, a ray of fight will travel from a point A in the air to a point B in the water by a path ACB that minimizes the time taken. Show that
sin
θ
1
sin
θ
2
=
v
1
v
2
where
θ
1
(the angle of incidence) and
θ
2
(the angle of refraction) are as shown. This equation is known as Snell’s Law.
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Area Between The Curve Problem No 1 - Applications Of Definite Integration - Diploma Maths II; Author: Ekeeda;https://www.youtube.com/watch?v=q3ZU0GnGaxA;License: Standard YouTube License, CC-BY