Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 38, Problem 32PQ
To determine
The position of Zak and Sallie so that Sallie can see a rainbow but Zak cannot.
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Chapter 38 Solutions
Physics for Scientists and Engineers: Foundations and Connections
Ch. 38.1 - Light travels from air into glass. Which sketch in...Ch. 38.2 - Prob. 38.2CECh. 38.3 - Prob. 38.3CECh. 38.6 - Prob. 38.4CECh. 38.7 - Prob. 38.5CECh. 38.9 - Prob. 38.6CECh. 38.9 - Prob. 38.7CECh. 38.10 - Prob. 38.8CECh. 38 - The Sun appears at an angle of 53.0 above the...Ch. 38 - Prob. 2PQ
Ch. 38 - Prob. 3PQCh. 38 - A light ray is incident on an interface between...Ch. 38 - Prob. 5PQCh. 38 - Prob. 6PQCh. 38 - Prob. 7PQCh. 38 - A ray of light enters a liquid from air. If the...Ch. 38 - Prob. 9PQCh. 38 - Figure P38.10 on the next page shows a...Ch. 38 - Prob. 11PQCh. 38 - Prob. 12PQCh. 38 - Prob. 13PQCh. 38 - Prob. 14PQCh. 38 - Prob. 15PQCh. 38 - A fish is 3.25 m below the surface of still water...Ch. 38 - N A fish is 3.25 m below the surface of still...Ch. 38 - A beam of monochromatic light within a fiber optic...Ch. 38 - Prob. 19PQCh. 38 - Prob. 20PQCh. 38 - Consider a light ray that enters a pane of glass...Ch. 38 - Prob. 22PQCh. 38 - Prob. 23PQCh. 38 - Prob. 24PQCh. 38 - Prob. 25PQCh. 38 - Prob. 26PQCh. 38 - Prob. 27PQCh. 38 - Prob. 28PQCh. 38 - The wavelength of light changes when it passes...Ch. 38 - Prob. 30PQCh. 38 - Light is incident on a prism as shown in Figure...Ch. 38 - Prob. 32PQCh. 38 - Prob. 33PQCh. 38 - Prob. 34PQCh. 38 - Prob. 35PQCh. 38 - Prob. 36PQCh. 38 - Prob. 37PQCh. 38 - A Lucite slab (n = 1.485) 5.00 cm in thickness...Ch. 38 - Prob. 39PQCh. 38 - Prob. 40PQCh. 38 - The end of a solid glass rod of refractive index...Ch. 38 - Prob. 42PQCh. 38 - Figure P38.43 shows a concave meniscus lens. If...Ch. 38 - Show that the magnification of a thin lens is...Ch. 38 - Prob. 45PQCh. 38 - Prob. 46PQCh. 38 - Prob. 47PQCh. 38 - The radius of curvature of the left-hand face of a...Ch. 38 - Prob. 49PQCh. 38 - Prob. 50PQCh. 38 - Prob. 51PQCh. 38 - Prob. 52PQCh. 38 - Prob. 53PQCh. 38 - Prob. 54PQCh. 38 - Prob. 55PQCh. 38 - Prob. 56PQCh. 38 - Prob. 57PQCh. 38 - Prob. 58PQCh. 38 - Prob. 59PQCh. 38 - Prob. 60PQCh. 38 - Prob. 61PQCh. 38 - Prob. 62PQCh. 38 - Prob. 63PQCh. 38 - Prob. 64PQCh. 38 - Prob. 65PQCh. 38 - Prob. 66PQCh. 38 - Prob. 67PQCh. 38 - Prob. 68PQCh. 38 - CASE STUDY Susan wears corrective lenses. The...Ch. 38 - A Fill in the missing entries in Table P38.70....Ch. 38 - Prob. 71PQCh. 38 - Prob. 72PQCh. 38 - Prob. 73PQCh. 38 - Prob. 74PQCh. 38 - An object 2.50 cm tall is 15.0 cm in front of a...Ch. 38 - Figure P38.76 shows an object placed a distance...Ch. 38 - Prob. 77PQCh. 38 - Prob. 78PQCh. 38 - Prob. 79PQCh. 38 - CASE STUDY A group of students is given two...Ch. 38 - A group of students is given two converging...Ch. 38 - Prob. 82PQCh. 38 - Two lenses are placed along the x axis, with a...Ch. 38 - Prob. 84PQCh. 38 - Prob. 85PQCh. 38 - Prob. 86PQCh. 38 - Prob. 87PQCh. 38 - Prob. 88PQCh. 38 - Prob. 89PQCh. 38 - Prob. 90PQCh. 38 - Prob. 91PQCh. 38 - Prob. 92PQCh. 38 - Prob. 93PQCh. 38 - Prob. 94PQCh. 38 - Prob. 95PQCh. 38 - Prob. 96PQCh. 38 - Prob. 97PQCh. 38 - A Fermats principle of least time for refraction....Ch. 38 - Prob. 99PQCh. 38 - Prob. 100PQCh. 38 - Prob. 101PQCh. 38 - Prob. 102PQCh. 38 - Prob. 103PQCh. 38 - Prob. 104PQCh. 38 - Curved glassair interfaces like those observed in...Ch. 38 - Prob. 106PQCh. 38 - Prob. 107PQCh. 38 - Prob. 108PQCh. 38 - Prob. 109PQCh. 38 - Prob. 110PQCh. 38 - Prob. 111PQCh. 38 - Prob. 112PQCh. 38 - Prob. 113PQCh. 38 - Prob. 114PQCh. 38 - The magnification of an upright image that is 34.0...Ch. 38 - Prob. 116PQCh. 38 - Prob. 117PQCh. 38 - Prob. 118PQCh. 38 - Prob. 119PQCh. 38 - Prob. 120PQCh. 38 - Prob. 121PQCh. 38 - Prob. 122PQCh. 38 - Prob. 123PQCh. 38 - Prob. 124PQCh. 38 - Prob. 125PQCh. 38 - Prob. 126PQCh. 38 - Light enters a prism of crown glass and refracts...Ch. 38 - Prob. 128PQCh. 38 - An object is placed a distance of 10.0 cm to the...
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- Explain why a fish in a spherical goldfish bowl appears larger than it really is.arrow_forwardConsider a common mirage formed by superheated air immediately above a roadway. A truck driver whose eyes are 2.00 m above the road, where n = 1.000 293, looks forward. She perceives the illusion of a patch of water ahead on the road. The road appears wet only beyond a point on the road at which her line of sight makes an angle of 1.20 below the horizontal. Find the index of refraction of the air immediately above the road surface.arrow_forwardThe level of water in a clear, colorless glass can easily be observed with the naked eye. The level of liquid helium in a clear glass vessel is extremely difficult to see with the naked eye. Explain. Hint: The index of refraction of liquid helium is close to that of air.arrow_forward
- Three sheets of plastic have unknown indices of refraction. Sheet 1 is placed on top of sheet 2, and a laser beam is directed onto the sheets from above so that it strikes the interface at an angle of 26.5 with the normal. The refracted beam in sheet 2 makes an angle of 31.7 with the normal. The experiment is repeated with sheet 3 on lop of sheet 2, and with the same angle of incidence, the refracted beam makes an angle of 36.7 with the normal. If the experiment is repeated again with sheet 1 on top of sheet 3, what is the expected angle of refraction in sheet 3? Assume the same angle of incidence.arrow_forwardThree sheets of plastic have unknown indices of refraction. Sheet 1 is placed on top of sheet 2, and a laser beam is directed onto the sheets from above so that it strikes the interface at an angle of 26.5 with the normal. The refracted beam in sheet 2 makes an angle of 31.7 with the normal. The experiment is repeated with sheet 3 on lop of sheet 2, and with the same angle of incidence, the refracted beam makes an angle of 36.7 with the normal. If the experiment is repeated again with sheet 1 on top of sheet 3, what is the expected angle of refraction in sheet 3? Assume the same angle of incidence.arrow_forwardPierre de Fermat (16011665) showed that whenever light travels from one point to another, its actual path is the path that requires the smallest time interval. This statement is known as Fermats principle. The simplest example is for light propagating in a homogeneous medium. It moves in a straight line because a straight line is the shortest distance between two points. Derive Snells law of refraction from Fermats principle. Proceed as follows. In Figure P34.54, a light ray travels from point P in medium 1 to point Q in medium 2. The two points are, respectively, at perpendicular distances a and b from the interface. The displacement from P to Q has the component d parallel to the interface, and we let x represent the coordinate of the point where the ray enters the second medium. Let t = 0 be the instant the light starts from P. (a) Show that the time at which the light arrives at Q is t=r1v1+r2v2=n1a2+x2c+n2b2+(dx)2c (b) To obtain the value of x for which t has its minimum value, differentiate t with respect to x and set the derivative equal to zero. Show that the result implies n1xa2+x2=n2(dx)b2+(dx)2 (c) Show that this expression in turn gives Snells law. n1sin1=n2sin2 Figure P34.54 Problems 54 and 55.arrow_forward
- Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardA scuba diver training in a pool looks at his instructor as shown in Figure 25.53. What angle does the ray from the instructor’s face make with the perpendicular to the water at the point where the ray enters? The angle between the ray in the water and the perpendicular to the water is 25.0°. Figure 25.53 A scuba diver in a pool and his trainer look at each other.arrow_forwardFigure P22.16 shows a light ray traveling in a slab of crown glass surrounded by air. The ray is incident on the right surface at an angle of 55 with the normal and then reflects from points A. B, and C. (a) At which of these points does part of the ray enter the air? (b) If the glass slab is surrounded by carbon disulfide, at which point does part of the ray enter the carbon disulfide?arrow_forward
- A Fermats principle of least time for refraction. A ray of light traveling in a medium with speed v1 leaves point A and strikes the boundary between the incident and transmitted media a horizontal distance x from point A as shown in Figure P38.98. The refracted ray travels with speed v2 in the second medium, eventually reaching point B. The horizontal distance between points A and B is L. a. Calculate the time t required for the light to travel from A to B in terms of the parameters labeled in the figure. b. Now take the derivative of t with respect to x. What is the condition for which the ray of light will take the shortest time to travel from A to B? Figure P38.98arrow_forwardEndoscopes are medical instruments used to examine the gastrointestinal tract and other cavities inside the body. The light required for examination is conducted from an outside source along a long, flexible bundle of optical fibers to the tip, where it exits and illuminates the internal cavity. A lens on the lip collects an image of the lighted cavity and another fiber bundle conducts the image back along the endoscope to an eyepiece for viewing (Fig. P22.52). If each fiber in the bundle has diameter d = 1.00 104 m and refractive index n = 1.40, find the smallest outside radius R permitted for a bend in the fiber if no light is to escape. Figure P22.52arrow_forward
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Laws of Refraction of Light | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=4l2thi5_84o;License: Standard YouTube License, CC-BY