# Steam enters an adiabatic, steady-state turbine at T = 300°C and P = 5 bar. The effluent from the turbine has P = 1 bar, and is a liquid–vapor mixture with q = 0.9. A. Find the difference between H ^ of the exiting stream and H ^ of the entering stream. B. In order to produce 100 MJ/min of work, what is the required flow rate of the entering stream?

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### Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
Publisher: Cengage Learning
ISBN: 9781111580704
BuyFind

### Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
Publisher: Cengage Learning
ISBN: 9781111580704

#### Solutions

Chapter
Section
Chapter 3.8, Problem 7E
Textbook Problem

## Steam enters an adiabatic, steady-state turbine at T = 300°C and P = 5 bar. The effluent from the turbine has P = 1 bar, and is a liquid–vapor mixture with q = 0.9.A. Find the difference between H ^ of the exiting stream and H ^ of the entering stream.B. In order to produce 100 MJ/min of work, what is the required flow rate of the entering stream?

Expert Solution

(A)

Interpretation Introduction

Interpretation:

The difference between specific enthalpy of exiting and entering stream of the steam.

Concept Introduction:

The exiting specific enthalpy (H^exiting) equation.

H^exiting=(1x)H^L+xH^V

Here, enthalpy in vapor phase is H^V, quality or dryness fraction is x, and enthalpy in liquid phase is H^L.

The difference between specific enthalpy (ΔH^) of exiting and entering stream of the steam.

ΔH^=H^exitingH^entering

Here, entering enthalpy is H^entering and exiting enthalpy is H^exiting.

### Explanation of Solution

Given information:

Refer appendix table A-4, “Saturated steam-Compressed liquid”, obtain the value of entering specific enthalpy of saturated liquid phase at a pressure of 5bar.

H^entering=640.1kJ/kg

Refer appendix table A-1, “Saturated steam-Pressure increments”, obtain the value of specific enthalpy in vapor phase at a pressure of 1bar.

H^V=2674.9kJ/kg

Refer appendix table A-1, “Saturated steam-Pressure increments”, obtain the value of specific enthalpy in liquid phase at a pressure of 1bar.

H^L=417.5kJ/kg

Write the expression to calculate the exiting specific enthalpy (H^exiting) of the steam.

H^exiting=(1x)H^L+xH^V        (1)

Substitute 0.9 for x, 417.5kJ/kg for H^L, and 2674.9kJ/kg for H^V in Equation (1).

H^exiting=(10

Expert Solution

(B)

Interpretation Introduction

Interpretation:

Mass flow rate (m˙) of the entering steam.

Concept Introduction:

Work done equation for the adiabatic turbine.

W˙m˙=H^exitingH^entering

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