   Chapter 3.9, Problem 1.5ACP

Chapter
Section
Textbook Problem

The percentage of oxygen in YBCO is adjusted by heating it in the presence of elemental oxygen. What mass of oxygen is required to convert 1.00 g YBa2Cu3O6.50 to YBa2Cu3O6.93?

Interpretation Introduction

Interpretation:

The mass of oxygen required to convert 1.00gYBa2Cu3O6.50 to YBa2Cu3O6.93 should be determined.

Concept introduction:

The number moles can be calculated by using following formula,

Numberofmoles =massmolarmass

Explanation

The given compound is YBa2Cu3O6.5(YBCO)The Molarmassof YBa2Cu3O6.5(YBCO)=658.126MolarmassofY=88.90Molarmassofbarium =137.32therefore, 2 moles of barium =2×137.32= 274.66Molarmassofcopper =63.543 moles of copper=3×63.54=190.62Molarmassofoxygen=15.996.5 moles of oxygen=6.93×15.99=103.935Numberofmoles =massmolarmassNumberofmoles (YBa2Cu3O6.5) =massmolarmassNumberofmoles (YBa2Cu3O6.5) =1658.126Numberofmoles (YBa2Cu3O6

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