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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The percentage of oxygen in YBCO is adjusted by heating it in the presence of elemental oxygen. What mass of oxygen is required to convert 1.00 g YBa2Cu3O6.50 to YBa2Cu3O6.93?

Interpretation Introduction

Interpretation:

The mass of oxygen required to convert 1.00gYBa2Cu3O6.50 to YBa2Cu3O6.93 should be determined.

Concept introduction:

The number moles can be calculated by using following formula,

Numberofmoles =massmolarmass

Explanation

  The given compound is YBa2Cu3O6.5(YBCO)The Molarmassof YBa2Cu3O6.5(YBCO)=658.126MolarmassofY=88.90Molarmassofbarium =137.32therefore, 2 moles of barium =2×137.32= 274.66Molarmassofcopper =63.543 moles of copper=3×63.54=190.62Molarmassofoxygen=15.996.5 moles of oxygen=6.93×15.99=103.935Numberofmoles =massmolarmassNumberofmoles (YBa2Cu3O6.5) =massmolarmassNumberofmoles (YBa2Cu3O6.5) =1658.126Numberofmoles (YBa2Cu3O6

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