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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The oxidation of sulfide ion to sulfate ion by oxygen can be carried out in the lab. What are the oxidation numbers of sulfur in these two ions?

Interpretation Introduction

Interpretation:

The oxidation number of sulfur in sulfide and sulphate ions should be determined.

Concept introduction:

An oxidizing agent gains the electrons and is reduced in a chemical reaction and it is electron acceptor.  A reducing agent loses electrons and is oxidized in a chemical reaction and it is electron donor.  The oxidation state is called as oxidation number, which describes degree of oxidation (loss of electrons) of an atom in a chemical compound.  Theoretically, the oxidation state is positive, negative or zero.

Explanation

The oxidation state of the sulfur is -2 in sulfide ion (S2-), which is shown below,

Net charge = Number of oxidation state ofsulfur atom-2 = (x)X= -2

The oxidation state of the sulfur is -2 in sulfate ion SO42-, which is shown below,

Net charge = Number of oxidation state ofsulfur atom + Number of oxidatio

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