   Chapter 4, Problem 102GQ

Chapter
Section
Textbook Problem

Cloth can be waterproofed by coating it with a silicone layer. This is done by exposing the cloth to (CH3)2SiCl2 vapor. The silicon compound reacts with OH groups on the doth to form a waterproofing film (density = 1.0 g/cm3) of [(CH3)2SiO]n, where n is a large integer number.n (CH3)2SiCl2 + 2n OH– → 2n Cl– + n H2O + [(CH3)2SiO]nThe coating is added layer by layer, with each layer of [(CH3)2SiO]n being 0.60 nm thick. Suppose you want to waterproof a piece of doth that is 3.00 square meters, and you want 250 layers of waterproofing compound on the cloth. What mass of (CH3)2SiCl2 do you need?

Interpretation Introduction

Interpretation:

The mass of (CH3)2SiCl2 needed to waterproof the given quantity of material has to be calculated.

Concept introduction:

• The mass of any material can be determined from its volume and density.  The mathematical relationship between mass, volume and density of material is,

Mass=Density×volume

• For chemical reaction balanced chemical equation is written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
Explanation

Cloth can be waterproofed by coating it with a silicone layer and it is done by exposing the cloth to (CH3)2SiCl2 vapor.

The silicon compound reacts with OH groups on the cloth to form a waterproofing film of [(CH3)2SiO]n where n is a large integer number.

The balanced equation for this reaction is,

n(CH3)2SiCl2+2nOH-2nCl-+nH2O+[(CH3)2SiO]n

The coating is added layer by layer, with each layer of [(CH3)2SiO]n being 0.60nm thick.

For 250 coats total thickness will be 0.6nm×250=150nmthick

1nm=1×10-7m150nm

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