   Chapter 4, Problem 10P

Chapter
Section
Textbook Problem

A 5.0-g bullet leaves the muzzle of a rifle with a speed of 320 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.82-m-long barrel of the rifle?

To determine
The force on the bullet.

Explanation

Section 1:

To determine: The acceleration of the bullet.

Answer: The acceleration of the bullet (a) is 6.24×104ms2 .

Explanation:

Given info: The mass of the train is 5.0 g and its velocity is 320 m/s. The total displacement of the bullet is 0.82 m.

From Newton’s equations of motion, the formula for acceleration is,

a=vf2vi22s (I)

• vf is the final velocity.
• vi is the initial velocity.
• s is the total displacement.

Substitute 320 m/s for vf , 0 m/s for vi and 0.82 m for s in Equation (I) to get a.

a=(320m/s)2(0m/s)22(0.82m)=(1024001.64)ms2=6.24×104ms2 (II)

The acceleration of the bullet is 6

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 