   # You mix 25.0 mL of 0.234 M FeCl 3 with 42.5 mL of 0.453 M NaOH. (a) What mass of Fe(OH) 3 (in grams) will precipitate from this reaction mixture? (b) One of the reactants (FeCl 3 or NaOH) is present in a stoichiometric excess. What is the molar concentration of the excess reactant remaining in solution after Fe(OH) 3 has been precipitated? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 118GQ
Textbook Problem
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## You mix 25.0 mL of 0.234 M FeCl3 with 42.5 mL of 0.453 M NaOH. (a) What mass of Fe(OH)3 (in grams) will precipitate from this reaction mixture? (b) One of the reactants (FeCl3 or NaOH) is present in a stoichiometric excess. What is the molar concentration of the excess reactant remaining in solution after Fe(OH)3 has been precipitated?

(a)

Interpretation Introduction

Interpretation:

The mass of Fe(OH)3 precipitated in the given reaction has to be determined.

Concept introduction:

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
• Amountof substance=Concentrationofsubstance×volumeofthesubstance
• Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.

### Explanation of Solution

Balanced chemical equation for the given reaction is,

FeCl3+3NaOH3NaCl+Fe(OH)3

From the balanced chemical equation it is clear that reactants and products react in a 1:1ratio

The amount (moles) of FeCl3 and NaOH used in the reaction can be calculated from its volume and concentration as follows,

AmountofFeCl3 =CFeCl3×VFeCl3 =0.234molL×0.025L =0.00585molFeCl3

AmountofNaOH =CNaOH×VNaOH =0.453molL×0.0425L =0.01925molNaOH

Using the stoichiometric factor the amount of Fe(OH)3 can be calculated from the amount of both the reactant.

Through this way it possible to know which reactant acts as the limiting reagent.

FeCl3 and Fe(OH)3 are same ratio (1:1)

The amount of Fe(OH)3 precipitated is,

0

(b)

Interpretation Introduction

Interpretation:

The molar concentration of excess reactant remaining in solution after the precipitation of Fe(OH)3 has to be determined.

Concept introduction:

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
• Amountof substance=Concentrationofsubstance×volumeofthesubstance
• Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.

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