   # Chromium(III) chloride forms many compounds with ammonia. To find the formula of one of these compounds, you titrate the NH 3 in the compound with standardized acid. Cr(NH 3 ) x Cl 3 (aq) + x HCl(aq) → x NH 4 + (aq) + Cr 3+ (aq) + ( x + 3) Cl − (aq) Assume that 24.26 mL of 1.500 M HCl is used to titrate 1.580 g of Cr(NH 3 ) x Cl 3 . What is the value of x ? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 127IL
Textbook Problem
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## Chromium(III) chloride forms many compounds with ammonia. To find the formula of one of these compounds, you titrate the NH3 in the compound with standardized acid.Cr(NH3)xCl3(aq) + x HCl(aq) → x NH4+(aq) + Cr3+(aq) + (x + 3) Cl−(aq)Assume that 24.26 mL of 1.500 M HCl is used to titrate 1.580 g of Cr(NH3)xCl3. What is the value of x?

Interpretation Introduction

Interpretation:

The value of x in the compound Cr(NH3)xCl3 involved in the given reaction has to be determined.

Concept introduction:

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.

Concentrationofsubstance=Amountof substancevolumeofthesubstance

### Explanation of Solution

Balanced chemical equation for the given reaction is,

Cr(NH3)xCl3(aq)+xHCl(aq)xNH4+(aq)+Cr(aq)3++(x+3)Cl(aq)

Amount of HCl can be calculated from its volume and concentration as follows,

AmountofHCl =CHCl×VHCl =1.500molL×0.02426L =0.3639molHCl

Molar mass of Cr(NH3)xCl3 can be calculated as,

58.93+(14.01+1.008×3)x+35.45×3=17.034x+165.28

Cr(NH3)xCl3 And  HCl are in stoichiometric ratio

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