   # A herbicide contains 2,4-D (2,4-dichlorophenoxyacetic acid), C 8 H 6 Cl 2 O 3 . A 1.236-g sample of the herbicide was decomposed to liberate the chlorine as Cl − ion. This was precipitated as AgCl, with a mass of 0.1840 g. What is the mass percent of 2,4-D in the sample? 2,4-D (2,4-dichlorophenoxyacetic acid) ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 129IL
Textbook Problem
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## A herbicide contains 2,4-D (2,4-dichlorophenoxyacetic acid), C8H6Cl2O3. A 1.236-g sample of the herbicide was decomposed to liberate the chlorine as Cl− ion. This was precipitated as AgCl, with a mass of 0.1840 g. What is the mass percent of 2,4-D in the sample? 2,4-D (2,4-dichlorophenoxyacetic acid)

Interpretation Introduction

Interpretation:

The mass percentage of 2,4-D(2,4-dichlorophenoxyaceticacid),C8H6Cl2O3 in the given sample of compound has to be determined.

Concept introduction:

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Mass percent of elements of a compound is the ratio of mass of element to the mass of whole compound and multiplied with hundred.
• Numberofmole=GivenmassofthesubstanceMolarmass

### Explanation of Solution

Here herbicide 2,4-D(2,4-dichlorophenoxyaceticacid) sample decomposed to liberate the chlorine as Cl ion. And it was precipitated as AgCl with a mass of 0.1840g

From the mass of  AgCl amount of 2,4-D(2,4-dichlorophenoxyaceticacid), and its mass can be calculated.

There is possibility to liberate 2molofCl from 1mol of C8H6Cl2O3.

Amount of AgCl produced in the reaction is,

0.1840g143.32g/mol=0.00128molAgCl

From this amount of AgCl the amount of C8H6Cl2O3 can be calculated as follows,

0

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