   Chapter 4, Problem 15PS

Chapter
Section
Textbook Problem

The reaction of methane and water is one way to prepare hydrogen for use as a fuel:CH4(g) + H2O(g) → CO(g) + 3 H2(g)If you begin with 995 g of CH4 and 2510 g of water, (a) Which reactant is the limiting reactant? (b) What is the maximum mass of H2 that can be prepared? (c) What mass of the excess reactant remains when the reaction is completed?

(a)

Interpretation Introduction

Interpretation:

The limiting reactant has to be identified for the given reaction.

Concept introduction:

Limiting reagent:

Limiting reagent is a reactant, which consumes completely in the chemical reaction.

The quantity of the product depends on this limiting reagent, it can be determined with

the help of balanced chemical equation for the reaction.

Explanation

Balanced chemical equation for the given reaction is,

CH4(g)+H2O(g)CO(g)+3H2(g)

To find the mass of product formed in the reaction, the amount of each reactant involved

in the given reaction should be determined.

Therefore,

AmountofCH4=995gCH4×1molCH416g=62molCH4AmountofH2O=2510gH2O×1molH2O18.0g=139

(b)

Interpretation Introduction

Interpretation:

The maximum mass of H2 that can be produced can be determined.

(c)

Interpretation Introduction

Interpretation:

Mass of excess reactant remains on completion of the reaction has to be determined.

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