   # In the thermite reaction, iron(III) oxide is reduced by aluminum to give molten iron Fe 2 O 3 (S) + 2 Al(S) → 2 Fe(l) + Al 2 O 3 (S) If you begin with 10.0 g of Fe 2 O 3 and 20.0 g of AI, (a) Which reactant is limiting? (b) What mass of Fe can be produced? (c) What mass of the excess reactant remains after the limiting reactant is consumed? (d) Set up an amounts table for this problem. ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 17PS
Textbook Problem
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## In the thermite reaction, iron(III) oxide is reduced by aluminum to give molten ironFe2O3(S) + 2 Al(S) → 2 Fe(l) + Al2O3(S)If you begin with 10.0 g of Fe2O3 and 20.0 g of AI, (a) Which reactant is limiting? (b) What mass of Fe can be produced? (c) What mass of the excess reactant remains after the limiting reactant is consumed? (d) Set up an amounts table for this problem.

(a)

Interpretation Introduction

Interpretation:

The limiting reactant of the reaction has to be identified.

Concept introduction:

Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction.  The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.

### Explanation of Solution

Balanced chemical equation for the given reaction is,

Fe2O3(s)+2Al(s)2Fe(l)+Al2O3(s)

To find the mass of product formed in the reaction, the amount of each reactant involved in the given reaction should be determined.

Therefore,

AmountofFe2O3=10.0gFe2O3×1molFe2O3159.69g=0.06262molFe2O3AmountofAl=20.0gAl×1molAl26.98g=0.74128molAl

The mass of Feand Al2O3 expected based on each reactant is,

0

(b)

Interpretation Introduction

Interpretation:

Mass of Fe produced in the reaction has to be determined.

Concept Introduction:

• The number of moles of any substance can be determined  using the equation,

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.

(c)

Interpretation Introduction

Interpretation:

Mass of excess reactant remains after the consumption of limiting reactant has to be calculated.

(d)

Interpretation Introduction

Interpretation:

Amount table for the given problem has to be set up.

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