   Chapter 4, Problem 23P

Chapter
Section
Textbook Problem

A 1.00 × 103-N crate is being pushed across a level floor at a constant speed by a force F → of 3.00 × 102 N at an angle of 20.0° below the horizontal, as shown in Figure P4.23a. (a) What is the coefficient of kinetic friction between the crate and the floor? (b) If the 3.00 × 102-N force is instead pulling the block at an angle of 20.0° above the horizontal, as shown in Figure P4.23b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in part (a). Figure P4.23

(a)

To determine
The co-efficient of kinetic friction.

Explanation

Given Info: Weight of the crate is 1.00×103N , the force of kinetic friction is 3.00×102N and the angle at which the force is applied is 20° .

Formula for co-efficient of kinetic friction is,

μk=FkN                                                       (I)

• Fk is force of kinetic friction.
• N is the normal force.

The free body diagram is given below.

From the above diagram,

N=Fsin20°+WFk=Fcos20°                                   (II)

• W is the weight of the crate.
• F is the applied force

(b)

To determine
The acceleration of the crate.

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