Loose Leaf for Organic Chemistry
Loose Leaf for Organic Chemistry
10th Edition
ISBN: 9781259626548
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education (edition 10)
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Chapter 4, Problem 26P
Interpretation Introduction

Interpretation:

The chirality of isomeric alcohol having molecular formula C6H14O is to be determined, and isomeric alcohols that are achiral need to be specified.

Concept introduction:

A chiral carbon atom is one which is attached to four different atoms or groups.

Different compounds having the same molecular formula are called isomers. They may differ in their constitution or arrangement of atoms in space.

Expert Solution & Answer
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Answer to Problem 26P

Solution:

Isomeric alcohols having the molecular formula C6H14O that are chiral:

Loose Leaf for Organic Chemistry, Chapter 4, Problem 26P , additional homework tip  1Loose Leaf for Organic Chemistry, Chapter 4, Problem 26P , additional homework tip  2

Isomeric alcohols having the molecular formula C6H14O that are achiral:

Loose Leaf for Organic Chemistry, Chapter 4, Problem 26P , additional homework tip  3

Explanation of Solution

There are 17 possible isomeric alcohols with molecular formula C6H14O. Out of these, 9 isomers are chiral, which are shown below:

Loose Leaf for Organic Chemistry, Chapter 4, Problem 26P , additional homework tip  4

The remaining 8 isomers are achiral, which are shown below:

Loose Leaf for Organic Chemistry, Chapter 4, Problem 26P , additional homework tip  5

Conclusion

An alcohol is said to be chiral if a carbon atom in it is attached to four different atoms or groups.

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Loose Leaf for Organic Chemistry

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