Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 4, Problem 26QP
Summary Introduction
To explain: The penetrance of third eye gene in the population of 19 aliens.
Introduction: The probability of the trait expression is called penetrance. It can also be defined as the probability of the expression of disease
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Recessive epistasis: In a cross between fruit flies that are both double heterozygous for modifier gene and coat color, in the total offspring of 192, how many fruit flies have gray- coat, white coat, and black coat? A recessive allele blocks the expression of the coat color of fruit flies. Show your answer and solution.
"Coat color in rats varies from white to black and includes many shades of gray in between. If the number of different coat colors possible is 9, how many genes are involved? "
Gene mapping using the Three-point Testcross
a) Given the following alleles that control seed traits:W = wrinkled G = green R = roundw = smooth g = yellow r = oval
b) Results of a cross with a triple heterozygote revealed the following phenotypes:30 smooth yellow round4 smooth green round958 wrinkled green round2 wrinkled yellow oval18 wrinkled yellow round946 smooth yellow oval16 smooth green oval26 wrinkled green oval
c) Determine the order of the genes and the distance between them in centiMorgan (cM).Construct a gene map to show your results.
TIP: Based on the phenotypes, determine the alleles in the gametes
Chapter 4 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 4.3 - Does a pedigree drawn from the available...Ch. 4.3 - Prob. 2EGCh. 4.7 - Did the fact that Prince Albert and Queen Victoria...Ch. 4.7 - Which members of the pedigree could have been...Ch. 4 - Pedigree analysis is a fundamental tool for...Ch. 4 - Pedigree analysis is a fundamental tool for...Ch. 4 - Pedigree analysis is a fundamental tool for...Ch. 4 - Pedigree Analysis Is a Basic Method in Human...Ch. 4 - Pedigree Analysis Is a Basic Method in Human...Ch. 4 - Pedigree Analysis Is a Basic Method in Human...
Ch. 4 - Pedigree Analysis Is a Basic Method in Human...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Use the following information to respond to the...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - A proband female with an unidentified disease...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Prob. 12QPCh. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Prob. 16QPCh. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Variations in Phenotype Expression Define...Ch. 4 - Prob. 26QPCh. 4 - Variations in Phenotype Expression A genetic...Ch. 4 - Variations in Phenotype Expression Explain how...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The gene controlling ABO blood type and the gene underlying nail-patella syndrome are said to show linkage. What does that mean in terms of their relative locations in the genome? What does it mean in terms of how the two traits are inherited with respect to each other?arrow_forwardThe most common allele of the β chain of hemoglobin in humans, ???,HbA, has glutamic acid at the sixth position. Two different amino acid substitutions at the sixth position produce two variants, ???HbS and ???,HbC, of the sickle‑cell allele. The ???HbS allele occurs when valine is substituted for glutamic acid, and the ???HbC allele occurs when lysine is substituted for glutamic acid. To answer the question, refer to the amino acid table. Match the class of amino acid and the chemical property to each possible amino acid. Not all answers will be placed.arrow_forwardRecalling the eye pigment pathway in Drosophila, identify the phenotypes of the flies with the following genotypes. (w=white, bw=brown, cn=cinnabar red, st=scarlet red, se=sepia brown)arrow_forward
- Colorblindness and hemophilia are both X-linked traits in humans. Explain how a female who has a defective color vision gene on one X chromosome and a defective blood clotting gene causing hemophilia on the other X chromosome can be neither a hemophiliac nor colorblind? Please discuss the effect of Gene dosage compensation in your answer and in your answer describe the molecular process by which this occurs.arrow_forwardSuppose that you are studying the role of Protein B, which you believe plays a role in regulating PCD/Apoptosis in mice. You create two lines of mutant mice. One (bb) is homozygous for a loss-of-function allele of gene B. The other (Bb) is heterozygous, with one wild-type allele and one loss-of function allele. Initially you pay particular attention to two phenotypes of the resulting mice:(i) The morphology of their paws (see picture) (ii) The size of their brains & shape of their skulls. The bb mice have unusually large brains and unusual protrusions from their skulls. Based on these data, does it appear that Protein B, when present and active, favors or inhibits PCD/Apoptosis?Briefly explain your reasoning. The answer should address both the paw and brain/skull data.arrow_forwardDiscuss the role of mutation in the origin of genetic polymorphisms. Suppose that a genetic polymorphism involves two alleles at frequencies of 0.45 and 0.55. Describe three different scenarios to explain these observed allele frequencies. You can propose that the mutations that produced the polymorphism are neutral, beneficial, or deleterious.arrow_forward
- VARIATIONS IN GENE EXPRESSION In humans, the glucose-6-phosphate dehydrogenase (G6PD) gene involved in sugar metabolism is X-linked. The dominant allele (G) codes for fast enzymes for normal cell functioning while the recessive allele (g) codes for slow enzymes, which are responsible for the reduced enzymatic activity of cells. However, the presence of slow enzymes has minimal effect in the overall functioning of heterozygotes, thus normal. Recessives, however, are more prone to oxidative reactions that speed up the cell damaging process, thus weak (but not lethal). If random inactivation occurs during dosage compensation, what would be the genotypes and phenotypes of the children of a heterozygous mother and a recessive father? Show COMPLETE cross.arrow_forwardVariations in Gene Expression In humans, the glucose-6-phosphate dehydrogenase (G6PD) gene involved in sugar metabolism is X-linked. The dominant allele (G) codes for fast enzymes for normal cell functioning while the recessive allele (g) codes for slow enzymes, which are responsible for the reduced enzymatic activity of cells. However, the presence of slow enzymes has minimal effect in the overall functioning of heterozygotes, thus normal. Recessives, however, are more prone to oxidative reactions that speed up the cell damaging process, thus weak (but not lethal). If random inactivation occurs during dosage compensation, what would be the genotypes and phenotypes of the children of a heterozygous mother and a recessive father? with COMPLETE crossarrow_forwardIn a study of a muscle disorder, several affected families exhibited vision problems, muscle weakness, and deafness (M. Zeviani et al. 1990. American Journal of Human Genetics 47:904–914). Analysis of the mtDNA from affected members of these families revealed that large numbers of their mtDNA molecules possessed deletions of varying lengths. Different members of the same family and even different mitochondria from the same person possessed deletions of different sizes, so the underlying defect appeared to be a tendency for the mtDNA of affected persons to have deletions. A pedigree of one of the families studied is shown below. The researchers concluded that this disorder is inherited as an autosomal dominant trait, and they mapped the diseasecausing gene to a position on chromosome 10 in the nucleus. Q. What characteristics of the pedigree rule out inheritance of a trait encoded by a gene in the mtDNA as the cause of this disorder?arrow_forward
- In a study of a muscle disorder, several affected families exhibited vision problems, muscle weakness, and deafness (M. Zeviani et al. 1990. American Journal of Human Genetics 47:904–914). Analysis of the mtDNA from affected members of these families revealed that large numbers of their mtDNA molecules possessed deletions of varying lengths. Different members of the same family and even different mitochondria from the same person possessed deletions of different sizes, so the underlying defect appeared to be a tendency for the mtDNA of affected persons to have deletions. A pedigree of one of the families studied is shown below. The researchers concluded that this disorder is inherited as an autosomal dominant trait, and they mapped the diseasecausing gene to a position on chromosome 10 in the nucleus. Q. Explain how a mutation in a nuclear gene might lead to deletions in mtDNA.arrow_forwardMultiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate. What epistatic ratio and what kind of epistasis is approximated in the F2? Propose a biochemical pathway for coat color in Labrador retrievers based on the type of epistasis. Correlate each genotype with the phenotype that would occur in your pathway. Also show the frequency of each genotype. A-B- A-bb aaB- aabbarrow_forward. Figure 18-14 presents haplotype data for the G6PD genein a worldwide sample of people.a. Draw a haplotype network for these haplotypes.Label the branches on which each SNP occurs.b. Which of the haplotypes has the most connectionsto other haplotypes?c. On what continents is this haplotype found?d. Counting the number of SNPs along the branchesof your network, how many differences are therebetween haplotypes 1 and 12?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Introduction to the NIOSH Manual of Analytical Methods Fifth edition; Author: Centers for Disease Control and Prevention (CDC);https://www.youtube.com/watch?v=B5rUrKLMoas;License: Standard Youtube License