Chapter 4, Problem 39PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# If 6.73 g of Na2CO3 is dissolved in enough water to make 250. mL of solution, what is the molar concentration of the sodium carbonate? What are the molar concentrations of the Na+ and CO32– ions?

Interpretation Introduction

Interpretation:

The molar concentration of Na2CO3Na+andCO32- ions should be determined.

Concept introduction:

• Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
• Molarity (M) of a solution is the number of gram moles of a solute present in one litre of the solution.

Molarity=MassperlitreMolecular mass

• A solution containing one gram mole or  0.1 gram of solute per litre of solution is called molar solution.
• Amount of substance (mol) can be determined by using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
Explanation

Amount of Na2CO3(in mol) can be calculated as follows,

â€‚Â 6.73â€‰gâ€‰Na2CO3â€‰Ã—1â€‰â€‰molâ€‰ofâ€‰â€‰Na2CO3â€‰106.0â€‰gâ€‰Na2CO3â€‰â€‰=â€‰0.0635â€‰molâ€‰Na2CO3

From the above calculated value it is possible to find the concentration of Na2CO3.

â€‚Â Concentrationâ€‰ofâ€‰â€‰Na2CO3â€‰=0.0635â€‰â€‰molâ€‰â€‰Na2CO3â€‰0.250â€‰Lâ€‰â€‰=â€‰0

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