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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

If 6.73 g of Na2CO3 is dissolved in enough water to make 250. mL of solution, what is the molar concentration of the sodium carbonate? What are the molar concentrations of the Na+ and CO32– ions?

Interpretation Introduction

Interpretation:

The molar concentration of Na2CO3Na+andCO32- ions should be determined.

Concept introduction:

  • Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
  • Molarity (M) of a solution is the number of gram moles of a solute present in one litre of the solution.

     Molarity=MassperlitreMolecular mass

  • A solution containing one gram mole or  0.1 gram of solute per litre of solution is called molar solution.
  • Amount of substance (mol) can be determined by using the equation

  Numberofmole=GivenmassofthesubstanceMolarmass

  • The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
  • For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
  • Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
Explanation

Amount of Na2CO3(in mol) can be calculated as follows,

  6.73gNa2CO3×1molofNa2CO3106.0gNa2CO3=0.0635molNa2CO3

From the above calculated value it is possible to find the concentration of Na2CO3.

  ConcentrationofNa2CO3=0.0635molNa2CO30.250L=0

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