a.
To obtain: The
a.
Answer to Problem 4.1.1RE
The probability that the outcome as 5 is 0.167.
Explanation of Solution
Given info:
A standard die is rolled.
Calculation:
Onrolling an 6-sided die has 6 different outcomes. That is, the outcomes are ‘1, 2, 3, 4, 5 and 6’
Here,
Let event A denote that the outcome is 5.
The formula for probability of event A is,
Substitute 1 for ‘Number of outcomes in A’ and 6 for ‘Total number of outcomes in the
Thus, the probability that the outcome is 5 is 0.167.
b.
To obtain: The probability ofgetting a number larger than 2.
b.
Answer to Problem 4.1.1RE
The probability ofgetting a number larger than 2 is 0.667.
Explanation of Solution
Calculation:
Here event B is defined as rolling a number larger than 2. Hence, the possible outcomes that the number larger than 2 are ‘3, 4,5 and 6’. That is, there are 4 outcomes for eventB.
The probability of event B is,
Substitute 4 for ‘Number of outcomes in B’ and 6 for ‘Total number of outcomes in the sample space’,
Thus, the probability of getting a number larger than 2 is 0.667.
c.
To obtain: The probability ofgetting an odd number.
c.
Answer to Problem 4.1.1RE
The probability of getting an odd number is 0.50.
Explanation of Solution
Calculation:
Here, the event C is defined as rolling an odd number. Hence, the possible outcomes for odd numbers are ‘1, 3, and 5’. That is, there are 3 outcomes for event C.
The probability of event C is,
Substitute 3 for ‘Number of outcomes in C’ and 6 for ‘Total number of outcomes in the sample space’,
Thus, the probability ofgetting an odd number is 0.50.
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