   Chapter 4, Problem 4.12P Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Solutions

Chapter
Section Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

In a shrinkage limit test, a sample of saturated clay was dried in the oven. The dry mass of the soil was 22.5 g. As shown in Figure 4.13, when the moisture content is at the shrinkage limit, the soil reaches a constant total volume, Vf. If Vf = 10.3 cm3, calculate the shrinkage limit of the soil. Given: Gs = 2.72

To determine

Find the shrinkage limit of the soil.

Explanation

Given information:

The dry mass of the soil Ms is 22.5 g.

Final volume of the soil Vf is 10.3cm3.

Specific gravity of the soil Gs is 2.72.

Calculation:

Consider the density of water as ρw=1g/cm3.

Determine the volume of the soil using the relation.

Vs=MsGsρw

Substitute 22.5 g for Ms, 2.72 for Gs, and 1g/cm3 for ρw.

Vs=22.52.72×1=8.27cm3

Determine the mass of water at the shrinkage limit using the relation.

Mw=ρwVw=ρwVv=ρw(VfVs)

Substitute 10

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