Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Answer to Problem 4.1P

Kinetic energy of beta particle = $156.875keV.$

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = $14.003241989$

Atomic mass of daughter beta particle = $14.003074004$

Energy of beta particle is equivalent to a change in masses of the atomic element.

  $\begin{array}{l}K.M_{max}\\ =[mP-ma]c^2\\ =[14.003241989-14.003074004]\times {(}^3\\ =2.5248\times 10-\text{14J}\\ =157.598keV.\end{array}$

Conclusion:

Most energetic Beta particles have a kinetic energy of $157.598keV.$