Package: Loose Leaf Organic Chemistry with Connect 2-year Access Card
Package: Loose Leaf Organic Chemistry with Connect 2-year Access Card
5th Edition
ISBN: 9781259729980
Author: SMITH
Publisher: MCG
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Chapter 4, Problem 4.1P
Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain 23,25,and27 carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only CC and CH bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is CnH2n+2.

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Answer to Problem 4.1P

The number of H atoms present in the saturated hydrocarbons of sex pheromone that contain 23,25,and27 carbon atoms are 48,52,and56 respectively.

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only CC and CH sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is CnH2n+2.

Where,

•  n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains 23 carbon atoms:

Substitute the value of number of carbon atoms (n) in general molecular formula of acyclic alkanes.

C23H(2×23)+2C23H48

Thus, the molecular formula of hydrocarbon that contains 23 carbon atoms is C23H48.

Hence, the number of hydrogen atoms is 48.

For the hydrocarbon of sex pheromone that contains 25 carbon atoms:

Substitute the value of number of carbon atoms (n) in general molecular formula of acyclic alkanes.

=C25H(2×25)+2=C25H52

Thus, the molecular formula of hydrocarbon that contains 25 carbon atoms is C25H52.

Hence, the number of hydrogen atoms is 52.

For the hydrocarbon of sex pheromone that contains 27 carbon atoms:

Substitute the value of number of carbon atoms (n) in general molecular formula of acyclic alkanes.

=C27H(2×27)+2=C27H56

Thus, the molecular formula of hydrocarbon that contains 27 carbon atoms is C27H56.

Hence, the number of hydrogen atoms is 56.

Conclusion

The number of H atoms in hydrocarbons of sex pheromone that contain 23,25,and27 carbon atoms are 48,52,and56 respectively.

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Chapter 4 Solutions

Package: Loose Leaf Organic Chemistry with Connect 2-year Access Card

Ch. 4 - Give the IUPAC name for each compound.Ch. 4 - Give the structure corresponding to each IUPAC...Ch. 4 - Arrange the following compounds in order of...Ch. 4 - Problem 4.14 Draw the staggered and eclipsed...Ch. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Problem 4.17 a. Draw the three staggered and...Ch. 4 - Problem 4.18 Rank the following conformations in...Ch. 4 - Problem 4.19 Consider rotation around the...Ch. 4 - Calculate the destabilization present in each...Ch. 4 - Problem 4.21 Classify the ring carbons as up or...Ch. 4 - Problem 4.22 Using the cyclohexane with the C’s...Ch. 4 - Draw a second chair conformation for each...Ch. 4 - Problem 4.24 Draw both conformations for and...Ch. 4 - Problem 4.25 Draw the structure for each compound...Ch. 4 - For cis-1, 3-diethylcyclobutane, draw a a...Ch. 4 - Prob. 4.27PCh. 4 - Problem 4.28 Consider . Draw structures f or the...Ch. 4 - Problem 4.29 Draw a chair conformation of...Ch. 4 - Prob. 4.30PCh. 4 - Draw the products of each combustion reaction.Ch. 4 - Explain why beeswax is insoluble in H2O, slightly...Ch. 4 - Prob. 4.33PCh. 4 - Name each alkane using the ball-and-stick model,...Ch. 4 - Consider the substituted cyclohexane shown in the...Ch. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - 4.38 Give the IUPAC name for each compound. a. c....Ch. 4 - 4.39 Give the structure and IUPAC name for each of...Ch. 4 - 4.40 Draw the structure corresponding to each...Ch. 4 - Prob. 4.41PCh. 4 - 4.42 Give the IUPAC name for each compound. a....Ch. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - 4.45 Which conformation in each pair is higher in...Ch. 4 - 4.46 Considering rotation around the bond...Ch. 4 - Prob. 4.47PCh. 4 - 4.48 (a) Using Newman projections, draw all...Ch. 4 - 4.49 Label the sites of torsional and steric...Ch. 4 - 4.50 Calculate the barrier to rotation for each...Ch. 4 - 4.51 The eclipsed conformation of is less...Ch. 4 - (a) Draw the anti and gauche conformations for...Ch. 4 - For each compound drawn below: a.Label each OH,Br...Ch. 4 - Draw the two possible chair conformations for...Ch. 4 - For each compound drawn below: a. Draw...Ch. 4 - 4.56 Convert each of the following structures into...Ch. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - 4.59 Classify each pair of compounds as...Ch. 4 - Classify each pair of compounds as constitutional...Ch. 4 - Prob. 4.61PCh. 4 - 4.62 Draw the three constitutional isomers having...Ch. 4 - Prob. 4.63PCh. 4 - 4.64 Draw the products of combustion of each...Ch. 4 - 4.65 Hydrocarbons like benzene are metabolized in...Ch. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Cyclopropane and cyclobutane have similar strain...Ch. 4 - Prob. 4.69PCh. 4 - Haloethanes (CH3CH2X,X=Cl,Br,I) have similar...Ch. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Consider the tricyclic structure B (a) Label each...Ch. 4 - Read Appendix B on naming branched alkyl...Ch. 4 - Read Appendix B on naming bicyclic compounds. Then...
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