Concept explainers
Calculate the gas pressure inside the platinum capsule after
Answer to Problem 4.35P
Gas pressure is
Explanation of Solution
When Radium-226 decay, it emits a particles each a particle is a helium nucleus with 2 electrons and forms helium gas which produces pressure in a capsule.
226 Ra emits 4 alpha particles per decay immediately after secular equilibrium and there is the formation of the fifth a particle.
The fraction of
Above carve shows a fraction of a to helium over 100 years.
Fraction=Area under curve/Total area
=
Integrating from
Fraction=
Four alpha particles emitted over
We know that,
To calculate the fraction of decay
Rearranging, (1) and (2)
Hence
To calculate helium atoms formed over
We have,
The dimension of the capsule,
The molecular weight of RaBr2,
The volume of RaBr2 is,
Volume available for gas=volume of capsule-volume of RaBr2
According to Ideal gas low
The pressure of helium formed by the decay of radium is 22.3 atmospheres. But originally capsule contains an air of 1 atmospheric pressure. Hence this initial pressure must be considered.
Thus, pressure=
Conclusion:
We can conclude about this problem that, when Radium-226 decays. It emits a particles having helium nucleus with two electrons and produces helium gas. Ideal gas law is used to calculate the pressure of helium gas. The gas pressure inside the capsule is 23.3 atm due to the formation of helium gas by the decay of radium.
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Chapter 4 Solutions
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