Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.3.8P
To determine
(a)
Check whether the compression member is adequate to support the loads using LRFD.
To determine
(b)
Check whether the compression member is adequate to support the loads using LRFD.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Read the question carefully and give me right solution according to the question.
A W12x79 of A573 Grade 60 (Fy=415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at the bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows:
A = 14,500 mm^2
Ix = 258.6 x 10^6 mm^4
Iy = 84.375 x 10^6 mm^4
Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.
Select a WT section for the compression member shown in Figure . The load is the total service load, with a live-to-dead load ratio of 2.5:1. Use Fy 5 50 ksi. a. Use LRFD.
b. Use ASD
How much service live load, in kips per foot, can be supported? The member weight is the only dead load. The axial compressive load consists of a service dead load of 10 kips and a service live load of 20 kips. Do not consider moment amplification. Bending is about the x axis, and the steel is A992. a. Use LRFD. b. Use ASD.
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
Knowledge Booster
Similar questions
- The steel is supported by the steel tie rod in AB beam B. Steel connection tension rod is placed 2 meters to the left of B and C sliding bracket is placed and P is loaded between AC It is. By ignoring the weights of beams and connecting rods, they can be determine the largest P load it can carry. The diameter of the BD rod is 16 mm. E = 200GPa I = 150x(10^6)mm^4arrow_forwardDesign the beam to resist the loads shown. Take fc = 9 MPa, fs = 124 MPa, n = 11, bar diameter = 20 mm. Take b = d/2. Use WSD method.arrow_forwardThe given frame is unbraced, and bending is about the x axis of each member. The axial dead load supported by column AB is 204 kips, and the axial live load is 408 kips. Fy = 50 ksi. Determine Kx for member AB. Use the stiffness reduction factor if possible. a. Use LRFD. b. Use ASDarrow_forward
- Determine the maximum axial compressive service load that can be supported if the live load is twice as large as the dead load. Use AISC Equation E3-2 or E3-3. a. Use LRFD. b. Use ASDarrow_forwardA compression member adopts a section of 530UB82.0 as shown in Fig. 1. Its steel grade is Grade 350. The effective lengths of the member are Lex=7.6 m and Ley=3.8 m. Determine the maximum design load of this compression member.arrow_forwardA W 360 x 744 is used as a beam to support a concrete floor system. The floor is to carry atotal load of 250 kPa. The beam is simply supported over a span of 6 m. Assume the beamis laterally supported over its length. Use A36 steel with Fy = 250 MPa. Allowabledeflection is L/360.a. Determine the center to center spacing of the beams without exceeding the allowableshear stress.b. Determine the center to center spacing of the beams without exceeding the allowablebending stress.c. Determine the center to center spacing of the beams without exceeding the allowabledeflection.arrow_forward
- A rectangular beam has a width b = 300 mm, and effective depth d = 500 mm and a total height h = 550 mm. The beam is reinforced with three bars ᶲ 20 mm. Compute the nominal strength of the beam cross section Mn and the design moment Mu. Use f’c = 35 MPa and Fy= 420 MPa.arrow_forward2. The beam shown in Figure P5.8-3 is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate for flexure and shear. a. Use LRFD. b. Use ASD.arrow_forwardA structural steel member is in the form of tee. bf= 300mm , tf= 100mm, bw= 200mm, d=300, fy= 248 Mpa. Determine the following: a. location of plastic neutral axis from the top of the beam b. plastic section modulus c. plastic moment capacityarrow_forward
- A cantilever beam AB of length L = 6.5 ft supportsa trapezoidal distributed load of peak intensity q,and minimum intensity q/2, that includes the weight ofthe beam (see figure). The beam is a steel W12 X14wide-flange shape (see Table F-1(a), Appendix F).Calculate the maximum permissible load q basedupon (a) an allowable bending stress σallow =18 ksiand (b) an allowable shear stress τallow = 7.5 ksi.Note: Obtain the moment of inertia and section modulusof the beam from Table F-1(a).arrow_forwardA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, pinned at the top fixed at bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 1. Calculate the critical slenderness ratio of the member. a. 26.208 b. 45.882 c. 36.706 d. 27.529 2. calculate the nominal axial load capacity of the column a. 3104 kN b. 4851 kN c. 4213 kN d. 5344 kN 3. calculalte the service axial dead load if the service axial live load is twice as that of the dead load. Use LRFD. a. 1354 kN b. 992 kN c. 1093 kN d. 634 kNarrow_forwardDetermine the Ultimate Moment Capacity of the given section with the following properties f'c=28 MPa fy=345 MPa Steel cover =d'=60mmarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning