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ChemistryOrganic And Biological Chemistry7th Edition

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Chapter 4, Problem 4.3EP
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Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079

Solutions

Chapter
Section
Problem 4.1EP
Problem 4.2EP
Problem 4.3EP
Problem 4.4EP
Problem 4.5EP
Problem 4.6EP
Problem 4.7EP
Problem 4.8EP
Problem 4.9EP
Problem 4.10EP
Problem 4.11EP
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Problem 4.14EP
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Problem 4.38EP
Problem 4.39EP
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Problem 4.111EP
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Problem 4.113EP
Problem 4.114EP
Problem 4.115EP
Problem 4.116EP
Problem 4.117EP
Problem 4.118EP
BuyFindarrow_forward

Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079
Textbook Problem

In terms of polarity, how does a carbon–oxygen double bond differ from a carbon–carbon double bond?

Interpretation Introduction

Interpretation:

In terms of polarity, how the carbon‑oxygen double bond differ from a carbon‑carbon double bond has to be explained.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

Organic And Biological Chemistry, Chapter 4, Problem 4.3EP

Explanation

Carbonyl group contains a carbon atom and an oxygen atom.  The bond between carbon and oxygen in a carbonyl group is a double bond.  There is a electronegativity difference between carbon atom and oxygen atom.  The electronegativity of oxygen is more than that of carbon.  Hence, the bond between carbon and oxygen in the carbonyl group is polarized.  Oxygen atom has a fractional negative charge and carbon atom has a fractional positive charge...

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Chapter 4 Solutions

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Sect-4.1 P-1QQSect-4.1 P-2QQSect-4.2 P-1QQSect-4.2 P-2QQSect-4.2 P-3QQSect-4.3 P-1QQSect-4.3 P-2QQSect-4.3 P-3QQSect-4.4 P-1QQSect-4.4 P-2QQ
Sect-4.4 P-3QQSect-4.4 P-4QQSect-4.4 P-5QQSect-4.5 P-1QQSect-4.5 P-2QQSect-4.5 P-3QQSect-4.5 P-4QQSect-4.5 P-5QQSect-4.6 P-1QQSect-4.6 P-2QQSect-4.6 P-3QQSect-4.7 P-1QQSect-4.7 P-2QQSect-4.8 P-1QQSect-4.8 P-2QQSect-4.9 P-1QQSect-4.9 P-2QQSect-4.10 P-1QQSect-4.10 P-2QQSect-4.10 P-3QQSect-4.10 P-4QQSect-4.11 P-1QQSect-4.11 P-2QQSect-4.11 P-3QQSect-4.11 P-4QQSect-4.11 P-5QQSect-4.12 P-1QQSect-4.12 P-2QQCh-4 P-4.1EPCh-4 P-4.2EPCh-4 P-4.3EPCh-4 P-4.4EPCh-4 P-4.5EPCh-4 P-4.6EPCh-4 P-4.7EPCh-4 P-4.8EPCh-4 P-4.9EPCh-4 P-4.10EPCh-4 P-4.11EPCh-4 P-4.12EPCh-4 P-4.13EPCh-4 P-4.14EPCh-4 P-4.15EPCh-4 P-4.16EPCh-4 P-4.17EPCh-4 P-4.18EPCh-4 P-4.19EPCh-4 P-4.20EPCh-4 P-4.21EPCh-4 P-4.22EPCh-4 P-4.23EPCh-4 P-4.24EPCh-4 P-4.25EPCh-4 P-4.26EPCh-4 P-4.27EPCh-4 P-4.28EPCh-4 P-4.29EPCh-4 P-4.30EPCh-4 P-4.31EPCh-4 P-4.32EPCh-4 P-4.33EPCh-4 P-4.34EPCh-4 P-4.35EPCh-4 P-4.36EPCh-4 P-4.37EPCh-4 P-4.38EPCh-4 P-4.39EPCh-4 P-4.40EPCh-4 P-4.41EPCh-4 P-4.42EPCh-4 P-4.43EPCh-4 P-4.44EPCh-4 P-4.45EPCh-4 P-4.46EPCh-4 P-4.47EPCh-4 P-4.48EPCh-4 P-4.49EPCh-4 P-4.50EPCh-4 P-4.51EPCh-4 P-4.52EPCh-4 P-4.53EPCh-4 P-4.54EPCh-4 P-4.55EPCh-4 P-4.56EPCh-4 P-4.57EPCh-4 P-4.58EPCh-4 P-4.59EPCh-4 P-4.60EPCh-4 P-4.61EPCh-4 P-4.62EPCh-4 P-4.63EPCh-4 P-4.64EPCh-4 P-4.65EPCh-4 P-4.66EPCh-4 P-4.67EPCh-4 P-4.68EPCh-4 P-4.69EPCh-4 P-4.70EPCh-4 P-4.71EPCh-4 P-4.72EPCh-4 P-4.73EPCh-4 P-4.74EPCh-4 P-4.75EPCh-4 P-4.76EPCh-4 P-4.77EPCh-4 P-4.78EPCh-4 P-4.79EPCh-4 P-4.80EPCh-4 P-4.81EPCh-4 P-4.82EPCh-4 P-4.83EPCh-4 P-4.84EPCh-4 P-4.85EPCh-4 P-4.86EPCh-4 P-4.87EPCh-4 P-4.88EPCh-4 P-4.89EPCh-4 P-4.90EPCh-4 P-4.91EPCh-4 P-4.92EPCh-4 P-4.93EPCh-4 P-4.94EPCh-4 P-4.95EPCh-4 P-4.96EPCh-4 P-4.97EPCh-4 P-4.98EPCh-4 P-4.99EPCh-4 P-4.100EPCh-4 P-4.101EPCh-4 P-4.102EPCh-4 P-4.103EPCh-4 P-4.104EPCh-4 P-4.105EPCh-4 P-4.106EPCh-4 P-4.107EPCh-4 P-4.108EPCh-4 P-4.109EPCh-4 P-4.110EPCh-4 P-4.111EPCh-4 P-4.112EPCh-4 P-4.113EPCh-4 P-4.114EPCh-4 P-4.115EPCh-4 P-4.116EPCh-4 P-4.117EPCh-4 P-4.118EP

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