Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 4, Problem 4.4.1P
To determine
The nominal compressive strength for
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A W21 x 101 is used as compression member with one end fixed and the other end free. The length is 10 feet. What is the nominal compressive strength if Fy 5 50 ksi? Note that this is a slender-element compression member, and the equations of AISC Section E7 must be use
An HSS 10x 8 x 3⁄16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute the nominal compressive strength for A500 Grade B steel (Fy 5 46 ksi).
4.4-1
AHSS10 × 8 × 3⁄16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute
the nominal compressive strength for A500 Grade B steel (Fy = 46 ksi). Note that thisis a slender-element compression member, and the equations of AISC Section E7 mustbe used.
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
A W21 × 101 is used as a compression member with one end fixed and the other end free. The length is 9m. Fy = 345 MPa.
1. What are the slenderness limits for the W-section?2. What is the nominal compressive strength?
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Compute the nominal compressive strength for a WT10.5 x 91 with an effective length of 18 feet with respect to each axis. Use A992 steel and the procedure of AISC Section E4 (not the column load tables).
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4.4-2 A W21 × 101 is used as a compression member with one end fixed and the other endfree. The length is 10 feet. What is the nominal compressive strength if Fy = 50 ksi?Note that this is a slender-element compression member, and the equations of AISCSection E7 must be used.
4.6-2 A 15-foot long column is pinned at the bottom and fixed against rotation but free totranslate at the top. It must support a service dead load of 100 kips and a service liveload of 100 kips.a. Select a W12 of A992 steel. Use the column load tables.1. Use LRFD.2. Use ASD.b. Select a W16 of A992 steel. Use the trial-and-error approach covered in Section 4.6.1. Use LRFD.2. Use ASD.
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An hss10x8x3/16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute the nominal compressive strength for a500 grade b steel (fy=46ksi). Note that this is a slender-element comoression member, and the equations of aisc section e7 must be used
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Use A992 steel and compute the nominal compressive strength of a WT12 x 51.5 with an effective length of4.88 m with respect to each axis. Evaluate using LRFD and ASD.
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A 50 ksi W14x22 is used as a compression member. The member is pinned at each end and it 8-feet long. Please determine the design strength of the compression member (LRFD). Hint: Local buckling will govern, so local buckling must be checked and the effective area (Ae) must be calculated to determine the nominal compressive strength (Pn)
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A compression member is built up from a W14x90 and a W10x49, both of A992 steel.a. Compute rx and ry for the built-up shape.b. Neglect flexural torsional buckling and compute the available strength for KxL = KyL = 30 feetusing LRFD.
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– A W460 × 177 is used as a compression member with one end fixed and the other end fixed against rotation but free to translate. The length is 3.70 meters. If A992 steel is used, what is the available compressive strength? Compute both the design strength for LRFD and the allowable strengthfor ASD.
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Read the question carefully and give me right solution according to the question.
A W12x79 of A573 Grade 60 (Fy=415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at the bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows:
A = 14,500 mm^2
Ix = 258.6 x 10^6 mm^4
Iy = 84.375 x 10^6 mm^4
Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.
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FIND USING ASD and LRFD
A W 14 x 500 is used as a beam to support a concrete floor system. The floor is to carrya total load of 120 kPa. The beam is simply supported over a span of 7 meters. Assumethe beam is laterally supported over its length, the allowable bending stress is 0.66Fy,and the allowable shear stress on gross section is 0.4Fy. Use A36 steel with Fy = 250MPa. Determine the following:a. center-to-center spacing of the beams without exceeding the allowable bendingstress;b. center-to-center spacing of the beams without exceeding the allowable shearstress.
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A W18 × 119 is used as a compression member with one end fixed and the other end fixed against rotation but free to translate. The length is 12 feet. If A992 steel is used, what is the available compressive strength?
a. Use AISC Equation, compute both the design strength for LRFD and the allowable strength for ASD.b. Use Table 4-22 from Part 4 of the Manual. Compute both the design strength for LRFD and the allowable strength for ASD.
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Does the column shown below have enough available strength to support the given working loads?Use LRFD.
Take E=20,232 ksi ,ry=2.3 in, K=1,Fy=59.0 ksi, Ag=32.7 in
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