   # What volume of 2.06 M KMnO 4 , in liters, contains 322 g of solute? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 44PS
Textbook Problem
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## What volume of 2.06 M KMnO4, in liters, contains 322 g of solute?

Interpretation Introduction

Interpretation:

It should be determined that the volume of 2.06MKMnO4 in litres, which contains

322g of solute.

Concept introduction:

• Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
• Molarity (M) of a solution is the number of gram moles of a solute present in one liter of the solution.

Molarity=NumberofmolesofelementVolumeofsolutioninlitres

Molarity=W×1000m×V

Where W, V and m are the mass of solute, volume of solution and molar mass of the solute respectively.

V=W×1000m×Molarity

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).

### Explanation of Solution

The volume of 2.06MKMnO4 in litres, which contains 322g of solute is calculated as,

Molarity (M) of a solution is the number of gram moles of a solute present in one litre of the solution.

Molarity=W×1000m×V

Where W, V and m are the mass of solute, volume of solution and molar mass of the solute respectively.

The volume of 2.06MKMnO4 in litres, which contains 322g of solute can be calculated as follows,

V=

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