Use implicit differentiation to show that a function defined implicitly by sin x + cos y = 2 y has a critical point whenever cos x = 0 . Then use either the first or second derivative test to classify these critical points as relative maxima or minima .
Use implicit differentiation to show that a function defined implicitly by sin x + cos y = 2 y has a critical point whenever cos x = 0 . Then use either the first or second derivative test to classify these critical points as relative maxima or minima .
Use implicit differentiation to show that a function defined implicitly by
sin
x
+
cos
y
=
2
y
has a critical point whenever
cos
x
=
0
. Then use either the first or second derivative test to classify these critical points as relative maxima or minima.
Formula Formula A function f(x) attains a local maximum at x=a , if there exists a neighborhood (a−δ,a+δ) of a such that, f(x)<f(a), ∀ x∈(a−δ,a+δ),x≠a f(x)−f(a)<0, ∀ x∈(a−δ,a+δ),x≠a In such case, f(a) attains a local maximum value f(x) at x=a .
Consider the function below. (If an answer does not exist, enter DNE.)
h(x) = 5x³-3x³
(a) Find the interval of increase. (Enter your answer using interval notation.)
(-00,0) U (1,00)
Find the interval of decrease. (Enter your answer using interval notation.)
(0,1)
(b) Find the local minimum value(s). (Enter your answers as a comma-separated list.)
-1.6
Find the local maximum value(s). (Enter your answers as a comma-separated list.)
1.6
(c) Find the inflection points.
(x, y) =
(smallest x-value)
(x, y)
(x, y) =
=
(largest x-value)
Find the interval where the graph is concave upward. (Enter your answer using interval notation.)
Find the interval where the graph is concave downward. (Enter your answer using interval notation.)
Topic: oriented surface integrals
Calculate
S
F-ds where
F = (4x³z, 4y³z, 3z¹)
y2
S is the surface of the solid bounded by the hemispheres z = √√25-x²- y², z=√16 - x² - y²
and the plane z = 0.
Chapter 4 Solutions
Calculus Early Transcendentals, Binder Ready Version
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