   # Billions of pounds of urea, CO ( NH 2 ) 2 , are produced annually for use as a fertilizer. The principal reaction employed is: 2NH 3 + CO 2 → CO ( NH 2 ) 2 + H 2 O By assuming unlimited amounts of CO 2 , how many moles of urea can be produced from each of the following amounts of NH 3 ? a . 2 mol NH 3 b . 0 .45 mol NH 3 c . 10 g NH 3 d . 2 .0 kg NH 3 ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 4, Problem 54E
Textbook Problem
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## Billions of pounds of urea, CO ( NH 2 ) 2 , are produced annually for use as a fertilizer. The principal reaction employed is: 2NH 3 + CO 2 →  CO ( NH 2 ) 2 + H 2 O By assuming unlimited amounts of CO2, how many moles of urea can be produced from each of the following amounts of NH 3 ? a . 2 mol NH 3 b . 0 .45 mol NH 3 c . 10 g NH 3 d . 2 .0 kg NH 3

Interpretation Introduction

Interpretation:

The number of moles of urea is to be determined in the given amounts of NH3.

Concept introduction:

The characteristic mass of a compound is the formula mass of the compound, which is obtained by adding the atomic masses of all atoms.

A conversion factor is a numerical ratio, which is used to change one unit into another.

The chemical formula represents the precise number of atoms in a molecule, but not their structural arrangement.

### Explanation of Solution

a) 2mol NH3

The equivalence is obtained between moles of NH3 and moles of urea with the help of the chemical formula as follows:

1mol urea2mol NH3

In order to obtain the moles of urea, the conversion factor proceeds as follows:

2mol NH3×1mol urea2mol NH3=1mol urea

Therefore, the number of moles of urea is 1 mol.

b) 0.45mol NH3

The equivalence is obtained between moles of NH3 and moles of urea with the help of the chemical formula as follows:

1mol urea2mol NH3

In order to obtain the moles of urea, the conversion factor proceeds as follows:

0.45mol NH3×1mol urea2mol NH3=0.23mol urea

Therefore, the moles of urea are 0.23 mol.

c) 10g NH3

The equivalence is obtained between grams of NH3 and moles of NH3 with the help of the chemical formula as follows:

1mol NH317.03g NH3

The equivalence is obtained between moles of NH3 and moles of urea with the help of the chemical formula as follows:

1mol urea2mol NH3

In order to obtain the moles of urea, the conversion factor proceeds as follows:

10g NH3×1mol NH317

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