Chapter 4, Problem 54PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Suppose you have 100.00 mL of a solution of a dye and transfer 2.00 mL of the solution to a 100.00-mL volumetric flask. After adding water to the 100.00 mL mark, you take 5.00 mL of that solution and again dilute to 100.00 Ml. If you find the dye concentration in the final diluted sample is 0.000158 M, what was the dye concentration in the original solution?

Interpretation Introduction

Interpretation:

The concentration of dye in the original solution after a series of dilution process should be determined.  The final concentration of dye is 0.000158M

Concept Introduction:

• Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
• Molarity (M) of a solution is the number of gram moles of a solute present in one liter of the solution.

Molarity=MassperlitreMolecular mass

• A solution containing one gram mole or 0.1 gram of solute per litre of solution is called molar solution.
• Concentrationofsubstance=Amountof substancevolumeofthesubstance
• Amountof substance=Concentrationofsubstance×volumeofthesubstance
Explanation

We have dye with 0.000158â€‰â€‰M concentration.

Amount of dye in the 100â€‰â€‰mL solution can be calculated as follows,

â€‚Â Amountâ€‰ofâ€‰dye = CdyeÃ—â€‰Vdye =â€‰0.000158â€‰â€‰molâ€‰dyeLâ€‰Ã—â€‰0.1â€‰L =â€‰0.0000158â€‰â€‰molâ€‰â€‰dye

The concentration of the solution in 5â€‰mL will be,

â€‚Â Concentrationâ€‰ofâ€‰dye =Amountâ€‰ofÂ dyevolumeâ€‰ofâ€‰theâ€‰dyeâ€‰â€‰ =0

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started