Chapter 4, Problem 61PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# What volume of 0.109 M HNO3, in milliliters, is required to react completely with 2.50 g of Ba(OH)2?2 HNO3(aq) + Ba(OH)2(s) → 2 H2O(l) + Ba(NO3)2(aq)

Interpretation Introduction

Interpretation:

It should be determine that the volume of 0.109MHNO3, in milliliters, which is required to react completely with 2.50gofBa(OH)2

Concept introduction:

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
Explanation

Volume of 0.109Mâ€‰HNO3, in milliliters, is required to react completely with 2.50â€‰gâ€‰ofâ€‰Ba(OH)2

Balanced chemical equation for the given reaction is

â€‚Â 2HNO3(aq)â€‰+â€‰Ba(OH)2(s)â€‰â†’â€‰2H2O(l)â€‰+â€‰Ba(NO3)2(aq)

The amount (moles) of Ba(OH)2 Â available can be calculated by using the equation

â€‚Â Numberâ€‰ofâ€‰moleâ€‰=Givenâ€‰massâ€‰ofâ€‰theâ€‰substanceMolarâ€‰massâ€‰

â€‚Â 2.50gâ€‰â€‰Ba(OH)2â€‰Ã—1â€‰molâ€‰Ba(OH)2171.34â€‰â€‰gâ€‰Ba(OH)2â€‰â€‰=â€‰0.0146â€‰molâ€‰Ba(OH)2

By using the stoichiometric factor calculating the amount of HNO3 required based on the amount of Ba(OH)2 as follows,

â€‚Â 0

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