   Chapter 4, Problem 63PS

Chapter
Section
Textbook Problem

When an electric current is passed through an aqueous solution of NaCI, the valuable industrial chemicals H2(g), Cl2(g), and NaOH are produced.2 NaCI(aq) + 2 H2O(l) → H2(g) + Cl2(g) + 2 NaOH(aq)What mass of NaOH can be formed from 15.0 L of 0.35 M NaCI? What mass of chlorine is obtained?

Interpretation Introduction

Interpretation:

The mass of NaOHandCl2 (in gram) produced in the given reaction should be determined.

Concept introduction:

• Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
Explanation

Balanced chemical equation for the given reaction is,

2NaCl(aq)+2H2O(l)H2(g)+Cl2(g)+2NaOH(aq)

The mass of NaOHandCl2 produced can be determined by considering the amount of substance in both the reactant NaCl and H2O but here H2O is the limiting reagent. Therefore the mass of NaOHandCl2 produced is determined by considering the concentration of H2O only.

Therefore the mass of NaOH produced is,

(0.350molNaCl1L)×(15

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