   # What volume of 0.750 M Pb(NO 3 ) 2 , in milliliters, is required to react completely with 1.00 L of 2.25 M NaCI solution? The balanced equation is Pb(NO 3 ) 2 (aq) + 2 NaCI(aq) → PbCl 2 (s) + 2 NaNO 3 (aq) ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 67PS
Textbook Problem
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## What volume of 0.750 M Pb(NO3)2, in milliliters, is required to react completely with 1.00 L of 2.25 M NaCI solution? The balanced equation isPb(NO3)2(aq) + 2 NaCI(aq) → PbCl2(s) + 2 NaNO3(aq)

Interpretation Introduction

Interpretation:

It should be determined that the volume of 0.750MPb(NO3)2, in milliliters, which is required to react completely with 1.0Lof2.25MNaCl solution.

Concept introduction:

• Numberofmole=GivenmassofthesubstanceMolarmass
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).

Molarity=Amountofsolute(mol)Volumeofsolution(L)

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.

### Explanation of Solution

Balanced chemical equation for the given reaction is,

Pb(NO3)2(aq)+2NaCl(aq)PbCl2(s)+2Na(NO3)(aq)

There are 2.25molNaCl in 1.00L of 2.25MNaCl.

By using the stoichiometric factor calculating the amount of Pb(NO3)2 required based on the amount of NaCl as follows,

2.25molNaCl×1molPb(NO3)22molNaCl=1

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