   Chapter 4, Problem 80AP

Chapter
Section
Textbook Problem

A high diver of mass 70.0 kg steps off a board 10.0 m above the water and falls vertical to the water, starting from rest. If her downward motion is stopped 2.00 s after her feet first touch the water, what average upward force did the water exert on her?

To determine
The average upward force.

Explanation

Given Info: Mass of the diver is 70.0 kg. The height is 10.0 m. The time taken for the diver to reach water is 2.00 s.

The formula for the average force is,

Favg=maavgmg (I)

• aavg is the average acceleration.
• g is the acceleration due to gravity.
• m is the mass of the diver.

From Newton’s equation of motion, the final velocity is,

v=2gh (II)

• g is the acceleration due to gravity.
• h is the height.

The initial velocity at the time when the diver reaches the water is equal to the final velocity during his fall.

The formula for the average acceleration is,

aavg=v'vt (III)

• v' is the final velocity.
• v is the initial velocity.
• t is the time taken.

From Equations (I), (II) and (III),

Favg=m[(v'2ght)g]

Substitute 70

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