   Chapter 4, Problem 89AP

Chapter
Section
Textbook Problem

The parachute on a race car of weight 8 820 N opens at the end of a quarter-mile run when the car is traveling at 35.0 m/s. What total retarding force must be supplied by the parachute to stop the car in a distance of 1.00 × 103 m?

To determine
The total retarding force.

Explanation

Given Info: Weight of the car is 8820 N. Speed of the car is 35.0 ms/. Stopping distance is 1.00×103m .

The formula for the retarding force is,

|Fr|=(Wg)|a| (I)

• a is the acceleration.
• g is the acceleration due to gravity.
• W is the weight of the car.

From Newton’s equation of motion, the acceleration is,

a=v2u22s (II)

• v is the final velocity.
• u is the initial velocity.
• s is the stopping distance.

From Equations (I) and (II),

|Fr|=(Wg)|(v2u22s)|

Substitute 8820 N for W, 0 m/s for v, 35.0 m/s for u, 9

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