   Chapter 4, Problem 9P

Chapter
Section
Textbook Problem

As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 61.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 6.00 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine (a) the salmon’s acceleration and (b) the magnitude of the force F during this interval.

(a)

To determine
The salmon’s acceleration.

Explanation

Given info: The length of the salmon is 1.50 m. The mass of the salmon is 61.0 kg. The initial velocity of the fish is 3.00 m/s and the final velocity is 6.00 m/s.

From Newton’s equations of motion, the formula for acceleration is,

a=vf2vi22s                                                       (I)

• vf is the final velocity.
• vi is the initial velocity.
• s is the total displacement.

The total displacement is equal to two-thirds the length.

s=23(1.50m)=1.00m

Conclusion:

Substitute 6.00 m/s for vf , 3

(b)

To determine
The magnitude of the force.

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