   # Find the apportionment that would have resulted if the Huntington-Hill method (the one used for the 2010 census) had been used in 1790. See our companion site at CengageBrain.com for a spreadsheet that will help with the calculations. ### Mathematical Excursions (MindTap C...

4th Edition
Richard N. Aufmann + 3 others
Publisher: Cengage Learning
ISBN: 9781305965584

#### Solutions

Chapter
Section ### Mathematical Excursions (MindTap C...

4th Edition
Richard N. Aufmann + 3 others
Publisher: Cengage Learning
ISBN: 9781305965584
Chapter 4.1, Problem 4EE
Textbook Problem
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## Find the apportionment that would have resulted if the Huntington-Hill method (the one used for the 2010 census) had been used in 1790. See our companion site at CengageBrain.com for a spreadsheet that will help with the calculations.

To determine

Find the apportionment that would have resulted if the Huntington-Hill method (the one used for the 2010 census) had been used in 1790.

### Explanation of Solution

Given Information:

Hamilton Hill method

Concept used:

Standard Divisor=Total PopulationNumber of representatives

Calculation:

First calculate standard divisor

Standard Divisor=Total PopulationNumber of representatives

Therefore,

Standard Divisor= 236841+55540+70835+278514+475327+68705+141822+85533+ 331591+179570+432879+353523+206236+630560+684467+1+2+8+14+2+4+2+10+5+13+10+6+19+2=361592210534437.35

 State Population Number of Representatives State Quota n n+1 Geometric mean   n(n+1) Number of Representatives Connecticut 236,841 7 23684134437.35 ≈6.877 6 7 6.48 7 Delaware 55,540 1 5554034437.35 ≈1.612 1 2 1.41 2 Georgia 70,835 2 7083534437.35 ≈2.056 2 3 2.45 2 Maryland 278,514 8 27851434437.35 ≈8.087 8 9 8.49 8 Massachusetts 475,327 14 47532734437.35 ≈13.802 13 14 13.49 14 Kentucky 68,705 2 6870534437.35 ≈1.995 1 2 1.41 2 New Hampshire 141,822 4 14182234437

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